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Oracle 1z1-071 exam is designed to evaluate the candidate's knowledge and skills in the area of Oracle Database SQL. 1z1-071 exam is intended for individuals who wish to pursue a career as an Oracle Database Developer or Administrator. The Oracle 1z1-071 Exam is a certification exam that is globally recognized and highly valued in the IT industry.
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The Oracle 1z1-071 Exam comprises 73 multiple-choice questions and is timed for 105 minutes. 1z1-071 exam is divided into six sections, each with its set of questions. The first section tests the candidates' knowledge of SQL SELECT statements, including the use of basic functions, expressions, and clauses. The second section tests the candidates' knowledge of SQL DML statements, including the use of INSERT, UPDATE, DELETE, and MERGE statements. The third section tests the candidates' knowledge of SQL Joins, including inner, outer, and self-joins.
Oracle Database SQL Sample Questions (Q183-Q188):
NEW QUESTION # 183
View the exhibit and examine the structure of the PROMOTIONStable.
You have to generate a report that displays the promo name and start date for all promos that started after the last promo in the 'INTERNET' category.
Which query would give you the required output?
SELECT promo_name, promo_begin_date FROM promotions
- A. SELESELECT promo_name, promo_begin_date FROM promotions
WHERE promo_begin_date IN (SELECT promo_begin_date
FROM promotions
WHERE promo_category= 'INTERNET');
SELECT promo_name, promo_begin_date FROM promotions - B. WHERE promo_begin_date > ALL (SELECT promo_begin_date
FROM promotions
WHERE promo_category = 'INTERNET');
SELECT promo_name, promo_begin_date FROM promotions - C. WHERE promo_begin_date> ANY (SELECT promo_begin_date
FROM promotions
WHERE promo_category= 'INTERNET'); - D. WHERE promo_begin_date> ALL (SELECT MAX (promo_begin_date)
FROM promotions) AND
promo_category= 'INTERNET';
Answer: B
Explanation:
Explanation
NEW QUESTION # 184
Examine these statements which execute successfully:
Both statements display departments ordered by their average salaries.
Which two are true?
- A. Only the second statement will execute successfully if you add E.AVG_SAL to the select list.
- B. Both statements will execute successfully If you add e.avg_sal to the select list.
- C. Both statements will display departments with no employees.
- D. Only the first statement will display departments with no employees.
- E. Only the second statement will display departments with no employees.
- F. Only the first statement will execute successfully if you add E.AVG_SAK to the select list.
Answer: B,E
Explanation:
A . Only the second statement will display departments with no employees. This is true because the second statement uses a LEFT JOIN to include all departments from the departments table, even those without matching entries in the employees table. When there are no employees in a department, the AVG(salary) will be NULL, and the department will still be displayed1.
C . Both statements will execute successfully if you add e.avg_sal to the select list. This is correct. Both statements calculate e.avg_sal as an average salary, either through a subquery or a join operation. Adding e.avg_sal to the select list will display the average salary alongside the departments. However, it's important to note that the first statement will not display departments with no employees because it does not use a join that would allow for NULL values from the employees table2.
Reference:
Understanding SQL JOINs - Stack Overflow1.
Oracle Documentation on JOIN Operations2.
Note: The other options are incorrect because:
B . The first statement will not display departments with no employees since it does not use a join that includes departments without matching employee records.
D . As explained, the first statement will not display departments with no employees.
E . There is a typo in the option; it should be E.AVG_SAL. Even if corrected, the first statement alone would not execute successfully because it does not include a join to bring in the avg_sal value.
F . The second statement will display departments with no employees, but the first statement will not, so this option is incorrect.
NEW QUESTION # 185
View the exhibit and examine the data in the PROJ_TASK_DETAILS table. (Choose the best answer.)
The PROJ_TASK_DETAILS table stores information about project tasks and the relation between them.
The BASED_ON column indicates dependencies between tasks.
Some tasks do not depend on the completion of other tasks.
You must generate a report listing all task IDs, the task ID of any task upon which it depends and the name of the employee in charge of the task upon which it depends.
Which query would give the required result?
- A. SELECT p.task_id, p.based_on, d.task_in_chargeFROM proj_task_details p FULL OUTER JOIN proj_task_details dON (p.based_on = d.task_id);
- B. SELECT p.task_id, p.based_on, d.task_in_chargeFROM proj_task_details p JOIN proj_task_details dON (p.task_id = d.task_id);
- C. SELECT p.task_id, p.based_on, d.task_in_chargeFROM proj_task_details p LEFT OUTER JOIN proj_task_details dON (p.based_on = d.task_id);
- D. SELECT p.task_id, p.based_on, d.task_in_chargeFROM proj_task_details p JOIN proj_task_details dON (p.based_on = d.task_id);
Answer: C
NEW QUESTION # 186
Which two statements are true about the rules of precedence for operators? (Choose two.)
- A. NULLS influence the precedence of operators in an expression
- B. Multiple parentheses can be used to override the default precedence of operators in an expression
- C. The concatenation operator | | is always evaluated before addition and subtraction in an expression
- D. Arithmetic operators with equal precedence area evaluated from left to right within an expression
- E. The + binary operator has the highest precedence in an expression in a SQL statement
Answer: B,D
NEW QUESTION # 187
The PRODUCT_INFORMATION table has a UNIT_PRICE column of data type NUMBER (8, 2).
Evaluate this SQL statement:
SELECT TO_CHAR(unit_price, '$9,999') FROM product_information;
Which two statements are true about the output?
- A. A row whose UNIT_PRICE column contains the value 1023.99 will be displayed as $1,023.
- B. A row whose UNIT_PRICE column contains the value 10235.99 will be displayed as $1,0236.
- C. A row whose UNIT_PRICE column contains the value 10235.99 will be displayed as $1,023.
- D. A row whose UNIT_PRICE column contains the value 10235.99 will be displayed as #######.
- E. A row whose UNIT_PRICE column contains the value 1023.99 will be displayed as $1,024.
Answer: A,D
NEW QUESTION # 188
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